What are the solutions to the equation 2x^2-16x+8=0 ?

The solutions to the equation 2x^2-16x+8=0 are x=2(2+sqrt(3)),x=2(2-sqrt(3))

Find the zeros of 2x^2-16x+8=0

The zeros of 2x^2-16x+8=0 are x=2(2+sqrt(3)),x=2(2-sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 16 x + 8 = 0

x = 2 (2 + 3), x = 2 (2 - 3)

Decimal Notation

x = 7.46410 \dots, x = 0.53589 \dots

Solution steps

2 x^{2} - 16 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

(- 16)^{2} - 4 \cdot 2 \cdot 8 = 83

x_{1, 2} = \frac{- ( - 16 ) \pm 8 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 8 3}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 8 3}{2 \cdot 2}

x = \frac{- ( - 16 ) + 8 3}{2 \cdot 2} : 2 (2 + 3)

x = \frac{- ( - 16 ) - 8 3}{2 \cdot 2} : 2 (2 - 3)

The solutions to the quadratic equation are:

x = 2 (2 + 3), x = 2 (2 - 3)

x^{2} - 288 x + 1136 = 0

250 = - 0.01 x^{2} + 50 x - 300

3 x^{2} + 22 x + 15 = 0

x^{2} - 12 x + 9 = 2 x - 4

- 13 m - m^{2} = 0

What are the solutions to the equation 2x^2-16x+8=0 ?
The solutions to the equation 2x^2-16x+8=0 are x=2(2+sqrt(3)),x=2(2-sqrt(3))
Find the zeros of 2x^2-16x+8=0
The zeros of 2x^2-16x+8=0 are x=2(2+sqrt(3)),x=2(2-sqrt(3))