What are the solutions to the equation x^2-3x=2x-6 ?

The solutions to the equation x^2-3x=2x-6 are x=3,x=2

Find the zeros of x^2-3x=2x-6

The zeros of x^2-3x=2x-6 are x=3,x=2

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x^{2} - 3 x = 2 x - 6

x = 3, x = 2

Solution steps

x^{2} - 3 x = 2 x - 6

Move

6

to the left side

x^{2} - 3 x + 6 = 2 x

Move

2 x

to the left side

x^{2} - 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

x = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

x = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 3, x = 2

3 x^{2} - 12 x + 36 = 0

2 s^{2} + s + 2 = 0

c \cdot c - c = 6

- 2 m^{2} + 2 m - 1 = 0

4 x^{2} - 6 x + 11 = 0

What are the solutions to the equation x^2-3x=2x-6 ?
The solutions to the equation x^2-3x=2x-6 are x=3,x=2
Find the zeros of x^2-3x=2x-6
The zeros of x^2-3x=2x-6 are x=3,x=2