What are the solutions to the equation -4w^2+16w-16=0 ?

The solutions to the equation -4w^2+16w-16=0 are w=2

Find the zeros of -4w^2+16w-16=0

The zeros of -4w^2+16w-16=0 are w=2

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- 4 w^{2} + 16 w - 16 = 0

w = 2

Solution steps

- 4 w^{2} + 16 w - 16 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 4 ) ( - 16 )}{2 ( - 4 )}

1 6^{2} - 4 (- 4) (- 16) = 0

w_{1, 2} = \frac{- 16 \pm 0}{2 ( - 4 )}

w = \frac{- 16}{2 ( - 4 )}

\frac{- 16}{2 ( - 4 )} = 2

w = 2

The solution to the quadratic equation is:

w = 2

3 x^{2} - 36 x + 81 = 0

x^{2} - 12 = 7 x

3 x^{2} + x - \frac{1}{2} = 0

x, x^{2} y - 9 y - x^{2} + 3 = 0

37500 X^{2} + 2117.1 X + 8177.4 = 0

What are the solutions to the equation -4w^2+16w-16=0 ?
The solutions to the equation -4w^2+16w-16=0 are w=2
Find the zeros of -4w^2+16w-16=0
The zeros of -4w^2+16w-16=0 are w=2