What are the solutions to the equation 2x^2+x-136=0 ?

The solutions to the equation 2x^2+x-136=0 are x=8,x=-17/2

Find the zeros of 2x^2+x-136=0

The zeros of 2x^2+x-136=0 are x=8,x=-17/2

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2 x^{2} + x - 136 = 0

x = 8, x = - \frac{17}{2}

Decimal Notation

x = 8, x = - 8.5

Solution steps

2 x^{2} + x - 136 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 136 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 136) = 33

x_{1, 2} = \frac{- 1 \pm 33}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 33}{2 \cdot 2}, x_{2} = \frac{- 1 - 33}{2 \cdot 2}

x = \frac{- 1 + 33}{2 \cdot 2} : 8

x = \frac{- 1 - 33}{2 \cdot 2} : - \frac{17}{2}

The solutions to the quadratic equation are:

x = 8, x = - \frac{17}{2}

x + \frac{x ^{2} + 4}{5} = 2

x^{2} + 22 x - 4 = 0

- 25 x^{2} + 4 x = 0

a, 14 (a^{2} + b^{2} + c^{2}) = (a + 2 b + 3 c)^{2}

x^{2} - 8 x + 25

What are the solutions to the equation 2x^2+x-136=0 ?
The solutions to the equation 2x^2+x-136=0 are x=8,x=-17/2
Find the zeros of 2x^2+x-136=0
The zeros of 2x^2+x-136=0 are x=8,x=-17/2