What are the solutions to the equation h^2+9h=0 ?

The solutions to the equation h^2+9h=0 are h=0,h=-9

Find the zeros of h^2+9h=0

The zeros of h^2+9h=0 are h=0,h=-9

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h^{2} + 9 h = 0

h = 0, h = - 9

Solution steps

h^{2} + 9 h = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 0 = 9

h_{1, 2} = \frac{- 9 \pm 9}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- 9 + 9}{2 \cdot 1}, h_{2} = \frac{- 9 - 9}{2 \cdot 1}

h = \frac{- 9 + 9}{2 \cdot 1} : 0

h = \frac{- 9 - 9}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

h = 0, h = - 9

x^{2} - 4 = - (4 - 2 x)

x (x - 16) + 63 = 0

q, p = 2 q^{2}

d, a \cdot [a + d] \cdot [a + 2 d] = 16

7 m^{2} + 2 = 170

What are the solutions to the equation h^2+9h=0 ?
The solutions to the equation h^2+9h=0 are h=0,h=-9
Find the zeros of h^2+9h=0
The zeros of h^2+9h=0 are h=0,h=-9