What are the solutions to the equation -12x^2+22x=0 ?

The solutions to the equation -12x^2+22x=0 are x=0,x= 11/6

Find the zeros of -12x^2+22x=0

The zeros of -12x^2+22x=0 are x=0,x= 11/6

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- 12 x^{2} + 22 x = 0

x = 0, x = \frac{11}{6}

Decimal Notation

x = 0, x = 1.83333 \dots

Solution steps

- 12 x^{2} + 22 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

2 2^{2} - 4 (- 12) \cdot 0 = 22

x_{1, 2} = \frac{- 22 \pm 22}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 22 + 22}{2 ( - 12 )}, x_{2} = \frac{- 22 - 22}{2 ( - 12 )}

x = \frac{- 22 + 22}{2 ( - 12 )} : 0

x = \frac{- 22 - 22}{2 ( - 12 )} : \frac{11}{6}

The solutions to the quadratic equation are:

x = 0, x = \frac{11}{6}

3 x^{2} + 11 x = - 6

x^{2} = 18 - 3 x

x, x^{2} + y^{2} + z^{2} = 8 z

2000 + 5 x^{2} - 200 x = 185.71

665 x^{2} + 20 x - 150 = 0

What are the solutions to the equation -12x^2+22x=0 ?
The solutions to the equation -12x^2+22x=0 are x=0,x= 11/6
Find the zeros of -12x^2+22x=0
The zeros of -12x^2+22x=0 are x=0,x= 11/6