What are the solutions to the equation -x^2-12x+9=0 ?

The solutions to the equation -x^2-12x+9=0 are x=-3(2+sqrt(5)),x=3(sqrt(5)-2)

Find the zeros of -x^2-12x+9=0

The zeros of -x^2-12x+9=0 are x=-3(2+sqrt(5)),x=3(sqrt(5)-2)

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- x^{2} - 12 x + 9 = 0

x = - 3 (2 + 5), x = 3 (5 - 2)

Decimal Notation

x = - 12.70820 \dots, x = 0.70820 \dots

Solution steps

- x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 1 ) \cdot 9}{2 ( - 1 )}

(- 12)^{2} - 4 (- 1) \cdot 9 = 65

x_{1, 2} = \frac{- ( - 12 ) \pm 6 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 12 ) - 6 5}{2 ( - 1 )}

x = \frac{- ( - 12 ) + 6 5}{2 ( - 1 )} : - 3 (2 + 5)

x = \frac{- ( - 12 ) - 6 5}{2 ( - 1 )} : 3 (5 - 2)

The solutions to the quadratic equation are:

x = - 3 (2 + 5), x = 3 (5 - 2)

x, z = x^{2} y^{2} - x y

t^{2} - 8 t + 10 = 0

x, f = (5 m - 10) 2 x^{2} + 3 x + 4

(3 x + 1) (x + 7) = 100

81 = 3 w^{2}

What are the solutions to the equation -x^2-12x+9=0 ?
The solutions to the equation -x^2-12x+9=0 are x=-3(2+sqrt(5)),x=3(sqrt(5)-2)
Find the zeros of -x^2-12x+9=0
The zeros of -x^2-12x+9=0 are x=-3(2+sqrt(5)),x=3(sqrt(5)-2)