What are the solutions to the equation x^2-5x=-7 ?

The solutions to the equation x^2-5x=-7 are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2

Find the zeros of x^2-5x=-7

The zeros of x^2-5x=-7 are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2

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x^{2} - 5 x = - 7

x = \frac{5}{2} + i \frac{3}{2}, x = \frac{5}{2} - i \frac{3}{2}

Solution steps

x^{2} - 5 x = - 7

Move

7

to the left side

x^{2} - 5 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 7 : 3 i

x_{1, 2} = \frac{- ( - 5 ) \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3 i}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3 i}{2 \cdot 1} : \frac{5}{2} + i \frac{3}{2}

x = \frac{- ( - 5 ) - 3 i}{2 \cdot 1} : \frac{5}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{3}{2}, x = \frac{5}{2} - i \frac{3}{2}

(37.15 - 1 x) \cdot (10.19 - 0.5 x) - (15.12)^{2} = 0

- 0.23 x^{2} + 3.68 x + 8.21 = 0

2 x^{2} + 18 x = 0

x^{2} - 5 x = 11

x, x^{2} + 3 p x + p^{2} = 79

What are the solutions to the equation x^2-5x=-7 ?
The solutions to the equation x^2-5x=-7 are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2
Find the zeros of x^2-5x=-7
The zeros of x^2-5x=-7 are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2