What are the solutions to the equation x^2-5x=11 ?

The solutions to the equation x^2-5x=11 are x=(5+sqrt(69))/2 ,x=(5-sqrt(69))/2

Find the zeros of x^2-5x=11

The zeros of x^2-5x=11 are x=(5+sqrt(69))/2 ,x=(5-sqrt(69))/2

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x^{2} - 5 x = 11

x = \frac{5 + 69}{2}, x = \frac{5 - 69}{2}

Decimal Notation

x = 6.65331 \dots, x = - 1.65331 \dots

Solution steps

x^{2} - 5 x = 11

Move

11

to the left side

x^{2} - 5 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 11) = 69

x_{1, 2} = \frac{- ( - 5 ) \pm 69}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 69}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 69}{2 \cdot 1}

x = \frac{- ( - 5 ) + 69}{2 \cdot 1} : \frac{5 + 69}{2}

x = \frac{- ( - 5 ) - 69}{2 \cdot 1} : \frac{5 - 69}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 69}{2}, x = \frac{5 - 69}{2}

x, x^{2} + 3 p x + p^{2} = 79

103.52 = 0.9 \cdot x \cdot 1 \cdot (\frac{0.35}{2})^{2} \cdot 420000 \cdot (1 - 0.59 x \cdot \frac{420}{21})

x^{2} + 10 x = 10

3.2 x^{2} - 7.1 x + 2.5 = 0

- 12 x^{2} + 48 x - 16 = 0

What are the solutions to the equation x^2-5x=11 ?
The solutions to the equation x^2-5x=11 are x=(5+sqrt(69))/2 ,x=(5-sqrt(69))/2
Find the zeros of x^2-5x=11
The zeros of x^2-5x=11 are x=(5+sqrt(69))/2 ,x=(5-sqrt(69))/2