What are the solutions to the equation y-(y^2)/2 =0 ?

The solutions to the equation y-(y^2)/2 =0 are y=0,y=2

Find the zeros of y-(y^2)/2 =0

The zeros of y-(y^2)/2 =0 are y=0,y=2

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y - \frac{y ^{2}}{2} = 0

y = 0, y = 2

Solution steps

y - \frac{y ^{2}}{2} = 0

Multiply both sides by

2

- y^{2} + 2 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 0 = 2

y_{1, 2} = \frac{- 2 \pm 2}{2 ( - 1 )}

Separate the solutions

y_{1} = \frac{- 2 + 2}{2 ( - 1 )}, y_{2} = \frac{- 2 - 2}{2 ( - 1 )}

y = \frac{- 2 + 2}{2 ( - 1 )} : 0

y = \frac{- 2 - 2}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

y = 0, y = 2

a^{2} + 6^{2} = 9^{2}

x, y^{2} - 4 x^{2} - 9 z^{2} = 0

x^{2} + (x + 5)^{2} = 53

8 x^{2} - 6 = 26

x, f x = 3 x^{2} + 5 x - 6

What are the solutions to the equation y-(y^2)/2 =0 ?
The solutions to the equation y-(y^2)/2 =0 are y=0,y=2
Find the zeros of y-(y^2)/2 =0
The zeros of y-(y^2)/2 =0 are y=0,y=2