What are the solutions to the equation x^2+(x+5)^2=53 ?

The solutions to the equation x^2+(x+5)^2=53 are x=2,x=-7

Find the zeros of x^2+(x+5)^2=53

The zeros of x^2+(x+5)^2=53 are x=2,x=-7

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x^{2} + (x + 5)^{2} = 53

x = 2, x = - 7

Solution steps

x^{2} + (x + 5)^{2} = 53

Expand

x^{2} + (x + 5)^{2} : 2 x^{2} + 10 x + 25

2 x^{2} + 10 x + 25 = 53

Move

53

to the left side

2 x^{2} + 10 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 28 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 28) = 18

x_{1, 2} = \frac{- 10 \pm 18}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 18}{2 \cdot 2}, x_{2} = \frac{- 10 - 18}{2 \cdot 2}

x = \frac{- 10 + 18}{2 \cdot 2} : 2

x = \frac{- 10 - 18}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = 2, x = - 7

8 x^{2} - 6 = 26

x, f x = 3 x^{2} + 5 x - 6

7 x^{2} - 10 x + 2 = 0

8 y^{2} = 968

0 = 3 v^{2} - 72

What are the solutions to the equation x^2+(x+5)^2=53 ?
The solutions to the equation x^2+(x+5)^2=53 are x=2,x=-7
Find the zeros of x^2+(x+5)^2=53
The zeros of x^2+(x+5)^2=53 are x=2,x=-7