What are the solutions to the equation 7x^2-10x+2=0 ?

The solutions to the equation 7x^2-10x+2=0 are x=(5+sqrt(11))/7 ,x=(5-sqrt(11))/7

Find the zeros of 7x^2-10x+2=0

The zeros of 7x^2-10x+2=0 are x=(5+sqrt(11))/7 ,x=(5-sqrt(11))/7

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7 x^{2} - 10 x + 2 = 0

x = \frac{5 + 11}{7}, x = \frac{5 - 11}{7}

Decimal Notation

x = 1.18808 \dots, x = 0.24048 \dots

Solution steps

7 x^{2} - 10 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 7 \cdot 2}{2 \cdot 7}

(- 10)^{2} - 4 \cdot 7 \cdot 2 = 211

x_{1, 2} = \frac{- ( - 10 ) \pm 2 11}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 11}{2 \cdot 7}, x_{2} = \frac{- ( - 10 ) - 2 11}{2 \cdot 7}

x = \frac{- ( - 10 ) + 2 11}{2 \cdot 7} : \frac{5 + 11}{7}

x = \frac{- ( - 10 ) - 2 11}{2 \cdot 7} : \frac{5 - 11}{7}

The solutions to the quadratic equation are:

x = \frac{5 + 11}{7}, x = \frac{5 - 11}{7}

8 y^{2} = 968

0 = 3 v^{2} - 72

4 x^{2} - 8 x - 6 = 0

x, x^{2} - 12 x + 32 = 0

7 = - x^{2} + 16

What are the solutions to the equation 7x^2-10x+2=0 ?
The solutions to the equation 7x^2-10x+2=0 are x=(5+sqrt(11))/7 ,x=(5-sqrt(11))/7
Find the zeros of 7x^2-10x+2=0
The zeros of 7x^2-10x+2=0 are x=(5+sqrt(11))/7 ,x=(5-sqrt(11))/7