What are the solutions to the equation 4x^2-8x-6=0 ?

The solutions to the equation 4x^2-8x-6=0 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2

Find the zeros of 4x^2-8x-6=0

The zeros of 4x^2-8x-6=0 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2

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4 x^{2} - 8 x - 6 = 0

x = \frac{2 + 10}{2}, x = \frac{2 - 10}{2}

Decimal Notation

x = 2.58113 \dots, x = - 0.58113 \dots

Solution steps

4 x^{2} - 8 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 6) = 410

x_{1, 2} = \frac{- ( - 8 ) \pm 4 10}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 10}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 10}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 10}{2 \cdot 4} : \frac{2 + 10}{2}

x = \frac{- ( - 8 ) - 4 10}{2 \cdot 4} : \frac{2 - 10}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 10}{2}, x = \frac{2 - 10}{2}

x, x^{2} - 12 x + 32 = 0

7 = - x^{2} + 16

5 x^{2} + 20 x + 8 = 0

m^{2} + 8 m + 6 = 0

8 x^{2} - 18 x + 7 = 0

What are the solutions to the equation 4x^2-8x-6=0 ?
The solutions to the equation 4x^2-8x-6=0 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2
Find the zeros of 4x^2-8x-6=0
The zeros of 4x^2-8x-6=0 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2