What are the solutions to the equation -x^2+3x+1=-x+1 ?

The solutions to the equation -x^2+3x+1=-x+1 are x=0,x=4

Find the zeros of -x^2+3x+1=-x+1

The zeros of -x^2+3x+1=-x+1 are x=0,x=4

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- x^{2} + 3 x + 1 = - x + 1

x = 0, x = 4

Solution steps

- x^{2} + 3 x + 1 = - x + 1

Move

1

to the left side

- x^{2} + 3 x = - x

Move

x

to the left side

- x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 1 )}, x_{2} = \frac{- 4 - 4}{2 ( - 1 )}

x = \frac{- 4 + 4}{2 ( - 1 )} : 0

x = \frac{- 4 - 4}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 0, x = 4

16 + x^{2} = 49

2 x^{2} - 14 x = - 15 - x^{2}

0 = - 4.9 x^{2} + 10 x + 100

x + x - \frac{xx}{100} = 36

2 x^{2} - 3 x - 5 = 0

What are the solutions to the equation -x^2+3x+1=-x+1 ?
The solutions to the equation -x^2+3x+1=-x+1 are x=0,x=4
Find the zeros of -x^2+3x+1=-x+1
The zeros of -x^2+3x+1=-x+1 are x=0,x=4