What are the solutions to the equation 2n^2-7n-21=0 ?

The solutions to the equation 2n^2-7n-21=0 are n=(7+sqrt(217))/4 ,n=(7-sqrt(217))/4

Find the zeros of 2n^2-7n-21=0

The zeros of 2n^2-7n-21=0 are n=(7+sqrt(217))/4 ,n=(7-sqrt(217))/4

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2 n^{2} - 7 n - 21 = 0

n = \frac{7 + 217}{4}, n = \frac{7 - 217}{4}

Decimal Notation

n = 5.43272 \dots, n = - 1.93272 \dots

Solution steps

2 n^{2} - 7 n - 21 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 21) = 217

n_{1, 2} = \frac{- ( - 7 ) \pm 217}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- ( - 7 ) + 217}{2 \cdot 2}, n_{2} = \frac{- ( - 7 ) - 217}{2 \cdot 2}

n = \frac{- ( - 7 ) + 217}{2 \cdot 2} : \frac{7 + 217}{4}

n = \frac{- ( - 7 ) - 217}{2 \cdot 2} : \frac{7 - 217}{4}

The solutions to the quadratic equation are:

n = \frac{7 + 217}{4}, n = \frac{7 - 217}{4}

(2 m - 1) x^{2} + m x + 15 = 0

2 - x (x + 4) = - 1 (x - 2)

(x + 7)^{2} = 15

1268.4 = 0.68 \cdot 100 \cdot X \cdot 1.79 \cdot (7.6 - 0.4 \cdot X)

v^{2} - v - 2 = 0

What are the solutions to the equation 2n^2-7n-21=0 ?
The solutions to the equation 2n^2-7n-21=0 are n=(7+sqrt(217))/4 ,n=(7-sqrt(217))/4
Find the zeros of 2n^2-7n-21=0
The zeros of 2n^2-7n-21=0 are n=(7+sqrt(217))/4 ,n=(7-sqrt(217))/4