What are the solutions to the equation v^2-v-2=0 ?

The solutions to the equation v^2-v-2=0 are v=2,v=-1

Find the zeros of v^2-v-2=0

The zeros of v^2-v-2=0 are v=2,v=-1

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v^{2} - v - 2 = 0

v = 2, v = - 1

Solution steps

v^{2} - v - 2 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

v_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, v_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

v = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

v = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

v = 2, v = - 1

3^{2} + b^{2} = 9^{2}

a, a^{2} + ab - 2 b^{2} = 0

13 + x^{2} = 10 x

6 πh x + 42 π x^{2} = 2160 π

2 x^{2} + 9 x = 12

What are the solutions to the equation v^2-v-2=0 ?
The solutions to the equation v^2-v-2=0 are v=2,v=-1
Find the zeros of v^2-v-2=0
The zeros of v^2-v-2=0 are v=2,v=-1