What are the solutions to the equation 3^2+b^2=9^2 ?

The solutions to the equation 3^2+b^2=9^2 are b=6sqrt(2),b=-6sqrt(2)

Find the zeros of 3^2+b^2=9^2

The zeros of 3^2+b^2=9^2 are b=6sqrt(2),b=-6sqrt(2)

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3^{2} + b^{2} = 9^{2}

b = 62, b = - 62

Decimal Notation

b = 8.48528 \dots, b = - 8.48528 \dots

Solution steps

3^{2} + b^{2} = 9^{2}

Move

3^{2}

to the right side

b^{2} = 72

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 72, b = - 72

72 = 62

- 72 = - 62

b = 62, b = - 62

a, a^{2} + ab - 2 b^{2} = 0

13 + x^{2} = 10 x

6 πh x + 42 π x^{2} = 2160 π

2 x^{2} + 9 x = 12

\frac{7 ^{2}}{2 5 ^{2}} + \frac{y ^{2}}{2 4 ^{2}} = 1

What are the solutions to the equation 3^2+b^2=9^2 ?
The solutions to the equation 3^2+b^2=9^2 are b=6sqrt(2),b=-6sqrt(2)
Find the zeros of 3^2+b^2=9^2
The zeros of 3^2+b^2=9^2 are b=6sqrt(2),b=-6sqrt(2)