What are the solutions to the equation 13+x^2=10x ?

The solutions to the equation 13+x^2=10x are x=5+2sqrt(3),x=5-2sqrt(3)

Find the zeros of 13+x^2=10x

The zeros of 13+x^2=10x are x=5+2sqrt(3),x=5-2sqrt(3)

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13 + x^{2} = 10 x

x = 5 + 23, x = 5 - 23

Decimal Notation

x = 8.46410 \dots, x = 1.53589 \dots

Solution steps

13 + x^{2} = 10 x

Move

10 x

to the left side

13 + x^{2} - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 10 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 13 = 43

x_{1, 2} = \frac{- ( - 10 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4 3}{2 \cdot 1} : 5 + 23

x = \frac{- ( - 10 ) - 4 3}{2 \cdot 1} : 5 - 23

The solutions to the quadratic equation are:

x = 5 + 23, x = 5 - 23

6 πh x + 42 π x^{2} = 2160 π

2 x^{2} + 9 x = 12

\frac{7 ^{2}}{2 5 ^{2}} + \frac{y ^{2}}{2 4 ^{2}} = 1

3 x^{2} + 80 x - 1600 = 0

4 (10 - x)^{2} = 5 x^{2}

What are the solutions to the equation 13+x^2=10x ?
The solutions to the equation 13+x^2=10x are x=5+2sqrt(3),x=5-2sqrt(3)
Find the zeros of 13+x^2=10x
The zeros of 13+x^2=10x are x=5+2sqrt(3),x=5-2sqrt(3)