What are the solutions to the equation -3t^2+9t=-810 ?

The solutions to the equation -3t^2+9t=-810 are t=-15,t=18

Find the zeros of -3t^2+9t=-810

The zeros of -3t^2+9t=-810 are t=-15,t=18

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- 3 t^{2} + 9 t = - 810

t = - 15, t = 18

Solution steps

- 3 t^{2} + 9 t = - 810

Move

810

to the left side

- 3 t^{2} + 9 t + 810 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 3 ) \cdot 810}{2 ( - 3 )}

9^{2} - 4 (- 3) \cdot 810 = 99

t_{1, 2} = \frac{- 9 \pm 99}{2 ( - 3 )}

Separate the solutions

t_{1} = \frac{- 9 + 99}{2 ( - 3 )}, t_{2} = \frac{- 9 - 99}{2 ( - 3 )}

t = \frac{- 9 + 99}{2 ( - 3 )} : - 15

t = \frac{- 9 - 99}{2 ( - 3 )} : 18

The solutions to the quadratic equation are:

t = - 15, t = 18

- 8 π r^{2} + 176 π r - 768 π = 0

1 + 2 x - 3 x^{2} = 0

2 z^{2} + 4 z + 2 = 0

x^{2} - 44 + 6 x = 5 + 6 x

24 = x (x - 2)

What are the solutions to the equation -3t^2+9t=-810 ?
The solutions to the equation -3t^2+9t=-810 are t=-15,t=18
Find the zeros of -3t^2+9t=-810
The zeros of -3t^2+9t=-810 are t=-15,t=18