What are the solutions to the equation 2z^2+4z+2=0 ?

The solutions to the equation 2z^2+4z+2=0 are z=-1

Find the zeros of 2z^2+4z+2=0

The zeros of 2z^2+4z+2=0 are z=-1

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2 z^{2} + 4 z + 2 = 0

z = - 1

Solution steps

2 z^{2} + 4 z + 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

4^{2} - 4 \cdot 2 \cdot 2 = 0

z_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 2}

z = \frac{- 4}{2 \cdot 2}

\frac{- 4}{2 \cdot 2} = - 1

z = - 1

The solution to the quadratic equation is:

z = - 1

x^{2} - 44 + 6 x = 5 + 6 x

24 = x (x - 2)

- 10 x + 14 = x^{2} - 5 x

10 x^{2} - 5 x = 2 x^{2} + 4 x

x, 3 x^{2} - 4 x - 3 = 0

What are the solutions to the equation 2z^2+4z+2=0 ?
The solutions to the equation 2z^2+4z+2=0 are z=-1
Find the zeros of 2z^2+4z+2=0
The zeros of 2z^2+4z+2=0 are z=-1