What are the solutions to the equation 10x^2-5x=2x^2+4x ?

The solutions to the equation 10x^2-5x=2x^2+4x are x= 9/8 ,x=0

Find the zeros of 10x^2-5x=2x^2+4x

The zeros of 10x^2-5x=2x^2+4x are x= 9/8 ,x=0

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10 x^{2} - 5 x = 2 x^{2} + 4 x

x = \frac{9}{8}, x = 0

Decimal Notation

x = 1.125, x = 0

Solution steps

10 x^{2} - 5 x = 2 x^{2} + 4 x

Move

4 x

to the left side

10 x^{2} - 9 x = 2 x^{2}

Move

2 x^{2}

to the left side

8 x^{2} - 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 9)^{2} - 4 \cdot 8 \cdot 0 = 9

x_{1, 2} = \frac{- ( - 9 ) \pm 9}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 9}{2 \cdot 8}, x_{2} = \frac{- ( - 9 ) - 9}{2 \cdot 8}

x = \frac{- ( - 9 ) + 9}{2 \cdot 8} : \frac{9}{8}

x = \frac{- ( - 9 ) - 9}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

x = \frac{9}{8}, x = 0

x, 3 x^{2} - 4 x - 3 = 0

11 x^{2} + 18 x + 7 = 0

2 x^{2} + x - 1081 = 0

x, x^{2} - x - 3 = 0

5 x^{2} - 4 x = - 1

What are the solutions to the equation 10x^2-5x=2x^2+4x ?
The solutions to the equation 10x^2-5x=2x^2+4x are x= 9/8 ,x=0
Find the zeros of 10x^2-5x=2x^2+4x
The zeros of 10x^2-5x=2x^2+4x are x= 9/8 ,x=0