What are the solutions to the equation solvefor x,x^2-x-3=0 ?

The solutions to the equation solvefor x,x^2-x-3=0 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2

Find the zeros of solvefor x,x^2-x-3=0

The zeros of solvefor x,x^2-x-3=0 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2

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x, x^{2} - x - 3 = 0

x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

Decimal Notation

x = 2.30277 \dots, x = - 1.30277 \dots

Solution steps

x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 3) = 13

x_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 1}

x = \frac{- ( - 1 ) + 13}{2 \cdot 1} : \frac{1 + 13}{2}

x = \frac{- ( - 1 ) - 13}{2 \cdot 1} : \frac{1 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

5 x^{2} - 4 x = - 1

4 0^{2} = 2 4^{2} + x^{2}

x^{2} = - 2 x + 80

y^{2} - 10 y + 41 = 0

λ^{2} + 4 = 0

What are the solutions to the equation solvefor x,x^2-x-3=0 ?
The solutions to the equation solvefor x,x^2-x-3=0 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2
Find the zeros of solvefor x,x^2-x-3=0
The zeros of solvefor x,x^2-x-3=0 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2