What are the solutions to the equation 40^2=24^2+x^2 ?

The solutions to the equation 40^2=24^2+x^2 are x=32,x=-32

Find the zeros of 40^2=24^2+x^2

The zeros of 40^2=24^2+x^2 are x=32,x=-32

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4 0^{2} = 2 4^{2} + x^{2}

x = 32, x = - 32

Solution steps

4 0^{2} = 2 4^{2} + x^{2}

Switch sides

2 4^{2} + x^{2} = 4 0^{2}

Move

2 4^{2}

to the right side

x^{2} = 1024

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1024, x = - 1024

1024 = 32

- 1024 = - 32

x = 32, x = - 32

x^{2} = - 2 x + 80

y^{2} - 10 y + 41 = 0

λ^{2} + 4 = 0

F = C D + C (D + C) + D (D + C)

x, (x^{2} - 2 m x + 5 m^{2}) \cdot 2 = 0

What are the solutions to the equation 40^2=24^2+x^2 ?
The solutions to the equation 40^2=24^2+x^2 are x=32,x=-32
Find the zeros of 40^2=24^2+x^2
The zeros of 40^2=24^2+x^2 are x=32,x=-32