What are the solutions to the equation λ^2+4=0 ?

The solutions to the equation λ^2+4=0 are λ=2i,λ=-2i

Find the zeros of λ^2+4=0

The zeros of λ^2+4=0 are λ=2i,λ=-2i

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λ^{2} + 4 = 0

λ = 2 i, λ = - 2 i

Solution steps

λ^{2} + 4 = 0

Move

4

to the right side

λ^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

λ = - 4, λ = - - 4

- 4 = 2 i

- - 4 = - 2 i

λ = 2 i, λ = - 2 i

F = C D + C (D + C) + D (D + C)

x, (x^{2} - 2 m x + 5 m^{2}) \cdot 2 = 0

2 x^{2} + 7 x + 16 = 0

36 x^{2} - 40 = 9

7 b^{2} = 343

What are the solutions to the equation λ^2+4=0 ?
The solutions to the equation λ^2+4=0 are λ=2i,λ=-2i
Find the zeros of λ^2+4=0
The zeros of λ^2+4=0 are λ=2i,λ=-2i