What are the solutions to the equation 144a^2+216a+81=0 ?

The solutions to the equation 144a^2+216a+81=0 are a=-3/4

Find the zeros of 144a^2+216a+81=0

The zeros of 144a^2+216a+81=0 are a=-3/4

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144 a^{2} + 216 a + 81 = 0

a = - \frac{3}{4}

Decimal Notation

a = - 0.75

Solution steps

144 a^{2} + 216 a + 81 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 216 \pm 21 6 ^{2} - 4 \cdot 144 \cdot 81}{2 \cdot 144}

21 6^{2} - 4 \cdot 144 \cdot 81 = 0

a_{1, 2} = \frac{- 216 \pm 0}{2 \cdot 144}

a = \frac{- 216}{2 \cdot 144}

\frac{- 216}{2 \cdot 144} = - \frac{3}{4}

a = - \frac{3}{4}

The solution to the quadratic equation is:

a = - \frac{3}{4}

(x - 1) (2 x + 2) = 0

0 = 18 + 6 t - 4 t^{2}

\frac{1}{4} x^{2} = - \frac{1}{2} x + 2

4 = x^{2} + 3

t^{2} + 3 = 0

What are the solutions to the equation 144a^2+216a+81=0 ?
The solutions to the equation 144a^2+216a+81=0 are a=-3/4
Find the zeros of 144a^2+216a+81=0
The zeros of 144a^2+216a+81=0 are a=-3/4