What are the solutions to the equation 4=x^2+3 ?

The solutions to the equation 4=x^2+3 are x=1,x=-1

Find the zeros of 4=x^2+3

The zeros of 4=x^2+3 are x=1,x=-1

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4 = x^{2} + 3

x = 1, x = - 1

Solution steps

4 = x^{2} + 3

Switch sides

x^{2} + 3 = 4

Move

3

to the right side

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

t^{2} + 3 = 0

x^{2} = 11 x + 126

s^{2} + 16 s + 100 = 0

x^{2} - 6 = 19

- x^{2} + 2 x - 3 = 4

What are the solutions to the equation 4=x^2+3 ?
The solutions to the equation 4=x^2+3 are x=1,x=-1
Find the zeros of 4=x^2+3
The zeros of 4=x^2+3 are x=1,x=-1