What are the solutions to the equation x^2+1/16 =1 ?

The solutions to the equation x^2+1/16 =1 are x=(sqrt(15))/4 ,x=-(sqrt(15))/4

Find the zeros of x^2+1/16 =1

The zeros of x^2+1/16 =1 are x=(sqrt(15))/4 ,x=-(sqrt(15))/4

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x^{2} + \frac{1}{16} = 1

x = \frac{15}{4}, x = - \frac{15}{4}

Decimal Notation

x = 0.96824 \dots, x = - 0.96824 \dots

Solution steps

x^{2} + \frac{1}{16} = 1

Move

\frac{1}{16}

to the right side

x^{2} = 1 - \frac{1}{16}

Simplify

1 - \frac{1}{16} : \frac{15}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{15}{16}, x = - \frac{15}{16}

\frac{15}{16} = \frac{15}{4}

- \frac{15}{16} = - \frac{15}{4}

x = \frac{15}{4}, x = - \frac{15}{4}

8 x^{2} + 5 x - 2 = 0

x^{2} - 105 x + 1260 = 0

x^{2} - 20 x = 17

x^{2} + 9 x + \frac{3}{4} = 0

- 10 x^{2} + 1760 x - 50000 = 0

What are the solutions to the equation x^2+1/16 =1 ?
The solutions to the equation x^2+1/16 =1 are x=(sqrt(15))/4 ,x=-(sqrt(15))/4
Find the zeros of x^2+1/16 =1
The zeros of x^2+1/16 =1 are x=(sqrt(15))/4 ,x=-(sqrt(15))/4