What are the solutions to the equation 8x^2+5x-2=0 ?

The solutions to the equation 8x^2+5x-2=0 are x=(-5+sqrt(89))/(16),x=(-5-sqrt(89))/(16)

Find the zeros of 8x^2+5x-2=0

The zeros of 8x^2+5x-2=0 are x=(-5+sqrt(89))/(16),x=(-5-sqrt(89))/(16)

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8 x^{2} + 5 x - 2 = 0

x = \frac{- 5 + 89}{16}, x = \frac{- 5 - 89}{16}

Decimal Notation

x = 0.27712 \dots, x = - 0.90212 \dots

Solution steps

8 x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 8 ( - 2 )}{2 \cdot 8}

5^{2} - 4 \cdot 8 (- 2) = 89

x_{1, 2} = \frac{- 5 \pm 89}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 5 + 89}{2 \cdot 8}, x_{2} = \frac{- 5 - 89}{2 \cdot 8}

x = \frac{- 5 + 89}{2 \cdot 8} : \frac{- 5 + 89}{16}

x = \frac{- 5 - 89}{2 \cdot 8} : \frac{- 5 - 89}{16}

The solutions to the quadratic equation are:

x = \frac{- 5 + 89}{16}, x = \frac{- 5 - 89}{16}

x^{2} - 105 x + 1260 = 0

x^{2} - 20 x = 17

x^{2} + 9 x + \frac{3}{4} = 0

- 10 x^{2} + 1760 x - 50000 = 0

c^{2} - c - 12 = 0

What are the solutions to the equation 8x^2+5x-2=0 ?
The solutions to the equation 8x^2+5x-2=0 are x=(-5+sqrt(89))/(16),x=(-5-sqrt(89))/(16)
Find the zeros of 8x^2+5x-2=0
The zeros of 8x^2+5x-2=0 are x=(-5+sqrt(89))/(16),x=(-5-sqrt(89))/(16)