What are the solutions to the equation c^2-c-12=0 ?

The solutions to the equation c^2-c-12=0 are c=4,c=-3

Find the zeros of c^2-c-12=0

The zeros of c^2-c-12=0 are c=4,c=-3

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c^{2} - c - 12 = 0

c = 4, c = - 3

Solution steps

c^{2} - c - 12 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

c_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, c_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

c = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

c = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

c = 4, c = - 3

- 4 x^{2} + 3 = 0

5 c^{2} + 4 c - 1 = 0

- 400 (x)^{2} + 9600 x + 79200 = 0

0.6 x^{2} + 1.4 x - 1 = 0

2 x^{2} + 3 x + 2 = 0

What are the solutions to the equation c^2-c-12=0 ?
The solutions to the equation c^2-c-12=0 are c=4,c=-3
Find the zeros of c^2-c-12=0
The zeros of c^2-c-12=0 are c=4,c=-3