What are the solutions to the equation 2m^2+8m=0 ?

The solutions to the equation 2m^2+8m=0 are m=0,m=-4

Find the zeros of 2m^2+8m=0

The zeros of 2m^2+8m=0 are m=0,m=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 m^{2} + 8 m = 0

m = 0, m = - 4

Solution steps

2 m^{2} + 8 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 0 = 8

m_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- 8 + 8}{2 \cdot 2}, m_{2} = \frac{- 8 - 8}{2 \cdot 2}

m = \frac{- 8 + 8}{2 \cdot 2} : 0

m = \frac{- 8 - 8}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

m = 0, m = - 4

x^{2} - 5 x - 5 + 8 = 0

x^{2} - 10 x - 14 = 0

7.63 x = 16 + x^{2}

4 x^{2} + 20 + 25 = 0

14 x^{2} + x - 6 = 2 x^{2}

What are the solutions to the equation 2m^2+8m=0 ?
The solutions to the equation 2m^2+8m=0 are m=0,m=-4
Find the zeros of 2m^2+8m=0
The zeros of 2m^2+8m=0 are m=0,m=-4