What are the solutions to the equation 14x^2+x-6=2x^2 ?

The solutions to the equation 14x^2+x-6=2x^2 are x= 2/3 ,x=-3/4

Find the zeros of 14x^2+x-6=2x^2

The zeros of 14x^2+x-6=2x^2 are x= 2/3 ,x=-3/4

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14 x^{2} + x - 6 = 2 x^{2}

x = \frac{2}{3}, x = - \frac{3}{4}

Decimal Notation

x = 0.66666 \dots, x = - 0.75

Solution steps

14 x^{2} + x - 6 = 2 x^{2}

Move

2 x^{2}

to the left side

12 x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 12 ( - 6 )}{2 \cdot 12}

1^{2} - 4 \cdot 12 (- 6) = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 \cdot 12}, x_{2} = \frac{- 1 - 17}{2 \cdot 12}

x = \frac{- 1 + 17}{2 \cdot 12} : \frac{2}{3}

x = \frac{- 1 - 17}{2 \cdot 12} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{3}{4}

16 x^{2} + 26 = 1

x^{2} + (x + 1)^{2} = 841

b^{2} = 8.7

- x^{2} - 5 x = 0

x (9 x - 4) = 13

What are the solutions to the equation 14x^2+x-6=2x^2 ?
The solutions to the equation 14x^2+x-6=2x^2 are x= 2/3 ,x=-3/4
Find the zeros of 14x^2+x-6=2x^2
The zeros of 14x^2+x-6=2x^2 are x= 2/3 ,x=-3/4