What are the solutions to the equation (15/17)^2+x^2=1 ?

The solutions to the equation (15/17)^2+x^2=1 are x= 8/17 ,x=-8/17

Find the zeros of (15/17)^2+x^2=1

The zeros of (15/17)^2+x^2=1 are x= 8/17 ,x=-8/17

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(\frac{15}{17})^{2} + x^{2} = 1

x = \frac{8}{17}, x = - \frac{8}{17}

Decimal Notation

x = 0.47058 \dots, x = - 0.47058 \dots

Solution steps

(\frac{15}{17})^{2} + x^{2} = 1

Expand

(\frac{15}{17})^{2} + x^{2} : \frac{225}{289} + x^{2}

\frac{225}{289} + x^{2} = 1

Move

\frac{225}{289}

to the right side

x^{2} = 1 - \frac{225}{289}

Simplify

1 - \frac{225}{289} : \frac{64}{289}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{64}{289}, x = - \frac{64}{289}

\frac{64}{289} = \frac{8}{17}

- \frac{64}{289} = - \frac{8}{17}

x = \frac{8}{17}, x = - \frac{8}{17}

40 r^{2} + 31 r + 6 = 0

F^{2} = 1 0^{2} + 1 0^{2} + 2 \cdot 10 \cdot 10 \cdot \frac{1}{2}

x, x^{2} + y^{2} - 6 x - 6 y + 27 = 0

3 g^{2} - 24 g + 27 = 0

a^{2} - 15 a + 56 = 0

What are the solutions to the equation (15/17)^2+x^2=1 ?
The solutions to the equation (15/17)^2+x^2=1 are x= 8/17 ,x=-8/17
Find the zeros of (15/17)^2+x^2=1
The zeros of (15/17)^2+x^2=1 are x= 8/17 ,x=-8/17