What are the solutions to the equation 8p^2+p=9 ?

The solutions to the equation 8p^2+p=9 are p=1,p=-9/8

Find the zeros of 8p^2+p=9

The zeros of 8p^2+p=9 are p=1,p=-9/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 p^{2} + p = 9

p = 1, p = - \frac{9}{8}

Decimal Notation

p = 1, p = - 1.125

Solution steps

8 p^{2} + p = 9

Move

9

to the left side

8 p^{2} + p - 9 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 8 ( - 9 )}{2 \cdot 8}

1^{2} - 4 \cdot 8 (- 9) = 17

p_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 8}

Separate the solutions

p_{1} = \frac{- 1 + 17}{2 \cdot 8}, p_{2} = \frac{- 1 - 17}{2 \cdot 8}

p = \frac{- 1 + 17}{2 \cdot 8} : 1

p = \frac{- 1 - 17}{2 \cdot 8} : - \frac{9}{8}

The solutions to the quadratic equation are:

p = 1, p = - \frac{9}{8}

a x^{2} + b x c = 0

3 x^{2} - 8 = 19

k^{2} = 121

x, x^{2} = 1 + y

9 r^{2} + 6 r = 1

What are the solutions to the equation 8p^2+p=9 ?
The solutions to the equation 8p^2+p=9 are p=1,p=-9/8
Find the zeros of 8p^2+p=9
The zeros of 8p^2+p=9 are p=1,p=-9/8