What are the solutions to the equation X^2+2X+5=0 ?

The solutions to the equation X^2+2X+5=0 are X=-1+2i,X=-1-2i

Find the zeros of X^2+2X+5=0

The zeros of X^2+2X+5=0 are X=-1+2i,X=-1-2i

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X^{2} + 2 X + 5 = 0

X = - 1 + 2 i, X = - 1 - 2 i

Solution steps

X^{2} + 2 X + 5 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 5 : 4 i

X_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 2 + 4 i}{2 \cdot 1}, X_{2} = \frac{- 2 - 4 i}{2 \cdot 1}

X = \frac{- 2 + 4 i}{2 \cdot 1} : - 1 + 2 i

X = \frac{- 2 - 4 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

X = - 1 + 2 i, X = - 1 - 2 i

a^{2} - 8 a = 0

- 2 x^{2} + 8 x + 24 = 0

5 = \frac{8 \cdot 0.03 \cdot 300 \cdot x ^{2}}{9.81 \cdot π ^{2} \cdot 0. 4 ^{5}}

7 x^{2} - 25 x + 12 = 0

0 = - v^{2} - 1 + v

What are the solutions to the equation X^2+2X+5=0 ?
The solutions to the equation X^2+2X+5=0 are X=-1+2i,X=-1-2i
Find the zeros of X^2+2X+5=0
The zeros of X^2+2X+5=0 are X=-1+2i,X=-1-2i