What are the solutions to the equation -2x^2+8x+24=0 ?

The solutions to the equation -2x^2+8x+24=0 are x=-2,x=6

Find the zeros of -2x^2+8x+24=0

The zeros of -2x^2+8x+24=0 are x=-2,x=6

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- 2 x^{2} + 8 x + 24 = 0

x = - 2, x = 6

Solution steps

- 2 x^{2} + 8 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 24}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 24 = 16

x_{1, 2} = \frac{- 8 \pm 16}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 16}{2 ( - 2 )}, x_{2} = \frac{- 8 - 16}{2 ( - 2 )}

x = \frac{- 8 + 16}{2 ( - 2 )} : - 2

x = \frac{- 8 - 16}{2 ( - 2 )} : 6

The solutions to the quadratic equation are:

x = - 2, x = 6

5 = \frac{8 \cdot 0.03 \cdot 300 \cdot x ^{2}}{9.81 \cdot π ^{2} \cdot 0. 4 ^{5}}

7 x^{2} - 25 x + 12 = 0

0 = - v^{2} - 1 + v

- 2 x^{2} + 64 = 0

2 x^{2} + x - 4 = 0

What are the solutions to the equation -2x^2+8x+24=0 ?
The solutions to the equation -2x^2+8x+24=0 are x=-2,x=6
Find the zeros of -2x^2+8x+24=0
The zeros of -2x^2+8x+24=0 are x=-2,x=6