What are the solutions to the equation -2x^2+64=0 ?

The solutions to the equation -2x^2+64=0 are x=4sqrt(2),x=-4sqrt(2)

Find the zeros of -2x^2+64=0

The zeros of -2x^2+64=0 are x=4sqrt(2),x=-4sqrt(2)

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- 2 x^{2} + 64 = 0

x = 42, x = - 42

Decimal Notation

x = 5.65685 \dots, x = - 5.65685 \dots

Solution steps

- 2 x^{2} + 64 = 0

Move

64

to the right side

- 2 x^{2} = - 64

Divide both sides by

- 2

x^{2} = 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 32, x = - 32

32 = 42

- 32 = - 42

x = 42, x = - 42

2 x^{2} + x - 4 = 0

- 12 x^{2} - 12 x - 3 = 0

x, 3 x^{2} y = λ x

3 y^{2} = - 16

- 3 x - 4 = 3 x^{2} - 13 x + 3

What are the solutions to the equation -2x^2+64=0 ?
The solutions to the equation -2x^2+64=0 are x=4sqrt(2),x=-4sqrt(2)
Find the zeros of -2x^2+64=0
The zeros of -2x^2+64=0 are x=4sqrt(2),x=-4sqrt(2)