What are the solutions to the equation -12x^2-12x-3=0 ?

The solutions to the equation -12x^2-12x-3=0 are x=-1/2

Find the zeros of -12x^2-12x-3=0

The zeros of -12x^2-12x-3=0 are x=-1/2

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- 12 x^{2} - 12 x - 3 = 0

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

- 12 x^{2} - 12 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 12 ) ( - 3 )}{2 ( - 12 )}

(- 12)^{2} - 4 (- 12) (- 3) = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 ( - 12 )}

x = \frac{- ( - 12 )}{2 ( - 12 )}

\frac{- ( - 12 )}{2 ( - 12 )} = - \frac{1}{2}

x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

x, 3 x^{2} y = λ x

3 y^{2} = - 16

- 3 x - 4 = 3 x^{2} - 13 x + 3

2 x^{2} - x - 10 = - 2

x, y = - 0.000009 x^{2} + 0.0104 x + 0.3928

What are the solutions to the equation -12x^2-12x-3=0 ?
The solutions to the equation -12x^2-12x-3=0 are x=-1/2
Find the zeros of -12x^2-12x-3=0
The zeros of -12x^2-12x-3=0 are x=-1/2