What are the solutions to the equation solvefor y,y^2=Cx^4+3x ?

The solutions to the equation solvefor y,y^2=Cx^4+3x are y=sqrt(Cx^4+3x),y=-sqrt(Cx^4+3x)

Find the zeros of solvefor y,y^2=Cx^4+3x

The zeros of solvefor y,y^2=Cx^4+3x are y=sqrt(Cx^4+3x),y=-sqrt(Cx^4+3x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

y, y^{2} = C x^{4} + 3 x

y = C x^{4} + 3 x, y = - C x^{4} + 3 x

Solution steps

y^{2} = C x^{4} + 3 x

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = C x^{4} + 3 x, y = - C x^{4} + 3 x

x, x^{2} - 3 x y^{3} = 10

(2 x - 3)^{2} - 118 + (x - 6)^{2} = (x - 5)^{2}

6 = x^{2} - 10 x

x, - x^{2} - 4 x + 12 = 0

5 x = 9 x^{2}

What are the solutions to the equation solvefor y,y^2=Cx^4+3x ?
The solutions to the equation solvefor y,y^2=Cx^4+3x are y=sqrt(Cx^4+3x),y=-sqrt(Cx^4+3x)
Find the zeros of solvefor y,y^2=Cx^4+3x
The zeros of solvefor y,y^2=Cx^4+3x are y=sqrt(Cx^4+3x),y=-sqrt(Cx^4+3x)