What are the solutions to the equation 3x-5x^2+8x=7+5x ?

The solutions to the equation 3x-5x^2+8x=7+5x are x= 3/5-i(sqrt(26))/5 ,x= 3/5+i(sqrt(26))/5

Find the zeros of 3x-5x^2+8x=7+5x

The zeros of 3x-5x^2+8x=7+5x are x= 3/5-i(sqrt(26))/5 ,x= 3/5+i(sqrt(26))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x - 5 x^{2} + 8 x = 7 + 5 x

x = \frac{3}{5} - i \frac{26}{5}, x = \frac{3}{5} + i \frac{26}{5}

Solution steps

3 x - 5 x^{2} + 8 x = 7 + 5 x

Refine

- 5 x^{2} + 11 x = 7 + 5 x

Move

5 x

to the left side

- 5 x^{2} + 6 x = 7

Move

7

to the left side

- 5 x^{2} + 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 5 ) ( - 7 )}{2 ( - 5 )}

Simplify

6^{2} - 4 (- 5) (- 7) : 226 i

x_{1, 2} = \frac{- 6 \pm 2 26 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 26 i}{2 ( - 5 )}, x_{2} = \frac{- 6 - 2 26 i}{2 ( - 5 )}

x = \frac{- 6 + 2 26 i}{2 ( - 5 )} : \frac{3}{5} - i \frac{26}{5}

x = \frac{- 6 - 2 26 i}{2 ( - 5 )} : \frac{3}{5} + i \frac{26}{5}

The solutions to the quadratic equation are:

x = \frac{3}{5} - i \frac{26}{5}, x = \frac{3}{5} + i \frac{26}{5}

5 x^{2} + 7 x + 9 = 0

x^{2} + 14 x + 49

- 4 x^{2} - 4 x - 3 = 0

3 y^{2} + 2 = 0

4 x^{2} + 12 x - 44 = 0

What are the solutions to the equation 3x-5x^2+8x=7+5x ?
The solutions to the equation 3x-5x^2+8x=7+5x are x= 3/5-i(sqrt(26))/5 ,x= 3/5+i(sqrt(26))/5
Find the zeros of 3x-5x^2+8x=7+5x
The zeros of 3x-5x^2+8x=7+5x are x= 3/5-i(sqrt(26))/5 ,x= 3/5+i(sqrt(26))/5