What are the solutions to the equation -4x^2-4x-3=0 ?

The solutions to the equation -4x^2-4x-3=0 are x=-1/2-i(sqrt(2))/2 ,x=-1/2+i(sqrt(2))/2

Find the zeros of -4x^2-4x-3=0

The zeros of -4x^2-4x-3=0 are x=-1/2-i(sqrt(2))/2 ,x=-1/2+i(sqrt(2))/2

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- 4 x^{2} - 4 x - 3 = 0

x = - \frac{1}{2} - i \frac{2}{2}, x = - \frac{1}{2} + i \frac{2}{2}

Solution steps

- 4 x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 4 ) ( - 3 )}{2 ( - 4 )}

Simplify

(- 4)^{2} - 4 (- 4) (- 3) : 42 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2 i}{2 ( - 4 )}, x_{2} = \frac{- ( - 4 ) - 4 2 i}{2 ( - 4 )}

x = \frac{- ( - 4 ) + 4 2 i}{2 ( - 4 )} : - \frac{1}{2} - i \frac{2}{2}

x = \frac{- ( - 4 ) - 4 2 i}{2 ( - 4 )} : - \frac{1}{2} + i \frac{2}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} - i \frac{2}{2}, x = - \frac{1}{2} + i \frac{2}{2}

3 y^{2} + 2 = 0

4 x^{2} + 12 x - 44 = 0

0.51 = \frac{12.96 + 28.09 - c ^{2}}{38.16}

2 p^{2} - 6 p + 7 = 0

- 4 x^{2} = - 64

What are the solutions to the equation -4x^2-4x-3=0 ?
The solutions to the equation -4x^2-4x-3=0 are x=-1/2-i(sqrt(2))/2 ,x=-1/2+i(sqrt(2))/2
Find the zeros of -4x^2-4x-3=0
The zeros of -4x^2-4x-3=0 are x=-1/2-i(sqrt(2))/2 ,x=-1/2+i(sqrt(2))/2