What are the solutions to the equation x^2+14x-10=5 ?

The solutions to the equation x^2+14x-10=5 are x=1,x=-15

Find the zeros of x^2+14x-10=5

The zeros of x^2+14x-10=5 are x=1,x=-15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 14 x - 10 = 5

x = 1, x = - 15

Solution steps

x^{2} + 14 x - 10 = 5

Move

5

to the left side

x^{2} + 14 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 15) = 16

x_{1, 2} = \frac{- 14 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 16}{2 \cdot 1}, x_{2} = \frac{- 14 - 16}{2 \cdot 1}

x = \frac{- 14 + 16}{2 \cdot 1} : 1

x = \frac{- 14 - 16}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 1, x = - 15

5 d (d + 1) + 6 = 0

x, x^{2} + 5 x - 6 = 0

4 x^{2} + 12 x = 0

8 = 2 x (x - 3)

w^{2} + 25 = 0

What are the solutions to the equation x^2+14x-10=5 ?
The solutions to the equation x^2+14x-10=5 are x=1,x=-15
Find the zeros of x^2+14x-10=5
The zeros of x^2+14x-10=5 are x=1,x=-15