What are the solutions to the equation 8=2x(x-3) ?

The solutions to the equation 8=2x(x-3) are x=4,x=-1

Find the zeros of 8=2x(x-3)

The zeros of 8=2x(x-3) are x=4,x=-1

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8 = 2 x (x - 3)

x = 4, x = - 1

Solution steps

8 = 2 x (x - 3)

Expand

2 x (x - 3) : 2 x^{2} - 6 x

8 = 2 x^{2} - 6 x

Switch sides

2 x^{2} - 6 x = 8

Move

8

to the left side

2 x^{2} - 6 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 8) = 10

x_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 10}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 10}{2 \cdot 2}

x = \frac{- ( - 6 ) + 10}{2 \cdot 2} : 4

x = \frac{- ( - 6 ) - 10}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

w^{2} + 25 = 0

x^{2} - 1 0^{- 8} x - 1 0^{- 14} = 0

4 x^{2} + 8 x - 5

x, ln (y) = - x^{2} + c

4 x^{2} + 8 x + 7

What are the solutions to the equation 8=2x(x-3) ?
The solutions to the equation 8=2x(x-3) are x=4,x=-1
Find the zeros of 8=2x(x-3)
The zeros of 8=2x(x-3) are x=4,x=-1