What are the solutions to the equation 4x^2-8x-13=0 ?

The solutions to the equation 4x^2-8x-13=0 are x=(2+sqrt(17))/2 ,x=(2-sqrt(17))/2

Find the zeros of 4x^2-8x-13=0

The zeros of 4x^2-8x-13=0 are x=(2+sqrt(17))/2 ,x=(2-sqrt(17))/2

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4 x^{2} - 8 x - 13 = 0

x = \frac{2 + 17}{2}, x = \frac{2 - 17}{2}

Decimal Notation

x = 3.06155 \dots, x = - 1.06155 \dots

Solution steps

4 x^{2} - 8 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 13 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 13) = 417

x_{1, 2} = \frac{- ( - 8 ) \pm 4 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 17}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 17}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 17}{2 \cdot 4} : \frac{2 + 17}{2}

x = \frac{- ( - 8 ) - 4 17}{2 \cdot 4} : \frac{2 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 17}{2}, x = \frac{2 - 17}{2}

8 n^{2} + 8 n + 2 = 0

y, x^{3} - x y^{2} + 2 y^{2} = 0

a^{2} + 2^{2} = 3^{2}

x, y^{- 1} = x^{2}

x^{2} + 17 x + 52 = 0

What are the solutions to the equation 4x^2-8x-13=0 ?
The solutions to the equation 4x^2-8x-13=0 are x=(2+sqrt(17))/2 ,x=(2-sqrt(17))/2
Find the zeros of 4x^2-8x-13=0
The zeros of 4x^2-8x-13=0 are x=(2+sqrt(17))/2 ,x=(2-sqrt(17))/2