What are the solutions to the equation x^2+17x+52=0 ?

The solutions to the equation x^2+17x+52=0 are x=-4,x=-13

Find the zeros of x^2+17x+52=0

The zeros of x^2+17x+52=0 are x=-4,x=-13

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x^{2} + 17 x + 52 = 0

x = - 4, x = - 13

Solution steps

x^{2} + 17 x + 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 52}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 52 = 9

x_{1, 2} = \frac{- 17 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 9}{2 \cdot 1}, x_{2} = \frac{- 17 - 9}{2 \cdot 1}

x = \frac{- 17 + 9}{2 \cdot 1} : - 4

x = \frac{- 17 - 9}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = - 4, x = - 13

3 x^{2} + 2 x + 1

10 m^{2} + 2 = 152

x^{2} - 25 x + 150 = 0

2 x^{2} + 9 x - 16 = 0

x, 1000000 x^{2} - 6200 x + 9 = 0

What are the solutions to the equation x^2+17x+52=0 ?
The solutions to the equation x^2+17x+52=0 are x=-4,x=-13
Find the zeros of x^2+17x+52=0
The zeros of x^2+17x+52=0 are x=-4,x=-13