What are the solutions to the equation x^2=45-4x ?

The solutions to the equation x^2=45-4x are x=5,x=-9

Find the zeros of x^2=45-4x

The zeros of x^2=45-4x are x=5,x=-9

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x^{2} = 45 - 4 x

x = 5, x = - 9

Solution steps

x^{2} = 45 - 4 x

Move

4 x

to the left side

x^{2} + 4 x = 45

Move

45

to the left side

x^{2} + 4 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 45 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 45) = 14

x_{1, 2} = \frac{- 4 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 14}{2 \cdot 1}, x_{2} = \frac{- 4 - 14}{2 \cdot 1}

x = \frac{- 4 + 14}{2 \cdot 1} : 5

x = \frac{- 4 - 14}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 5, x = - 9

(x - 3) (x + 7) = 11

2 x^{2} + 3 x - 20 = 0

2 x^{2} - 12 x + 4 = 0

x^{2} = 2 x - 8

4 (s - 3)^{2} = 5

What are the solutions to the equation x^2=45-4x ?
The solutions to the equation x^2=45-4x are x=5,x=-9
Find the zeros of x^2=45-4x
The zeros of x^2=45-4x are x=5,x=-9