What are the solutions to the equation 3y^2-17y+10=0 ?

The solutions to the equation 3y^2-17y+10=0 are y=5,y= 2/3

Find the zeros of 3y^2-17y+10=0

The zeros of 3y^2-17y+10=0 are y=5,y= 2/3

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3 y^{2} - 17 y + 10 = 0

y = 5, y = \frac{2}{3}

Decimal Notation

y = 5, y = 0.66666 \dots

Solution steps

3 y^{2} - 17 y + 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

(- 17)^{2} - 4 \cdot 3 \cdot 10 = 13

y_{1, 2} = \frac{- ( - 17 ) \pm 13}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 17 ) + 13}{2 \cdot 3}, y_{2} = \frac{- ( - 17 ) - 13}{2 \cdot 3}

y = \frac{- ( - 17 ) + 13}{2 \cdot 3} : 5

y = \frac{- ( - 17 ) - 13}{2 \cdot 3} : \frac{2}{3}

The solutions to the quadratic equation are:

y = 5, y = \frac{2}{3}

t^{2} + 2 t + 2 = 0

2 x^{2} - 6 = - 168

y, \frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

x (x - 15) + 54 = 0

x, x^{2} + y^{2} + 2 z^{2} = 1

What are the solutions to the equation 3y^2-17y+10=0 ?
The solutions to the equation 3y^2-17y+10=0 are y=5,y= 2/3
Find the zeros of 3y^2-17y+10=0
The zeros of 3y^2-17y+10=0 are y=5,y= 2/3