What are the solutions to the equation 4+6x-x^2=0 ?

The solutions to the equation 4+6x-x^2=0 are x=3-sqrt(13),x=3+sqrt(13)

Find the zeros of 4+6x-x^2=0

The zeros of 4+6x-x^2=0 are x=3-sqrt(13),x=3+sqrt(13)

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4 + 6 x - x^{2} = 0

x = 3 - 13, x = 3 + 13

Decimal Notation

x = - 0.60555 \dots, x = 6.60555 \dots

Solution steps

4 + 6 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 4 = 213

x_{1, 2} = \frac{- 6 \pm 2 13}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 13}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 13}{2 ( - 1 )}

x = \frac{- 6 + 2 13}{2 ( - 1 )} : 3 - 13

x = \frac{- 6 - 2 13}{2 ( - 1 )} : 3 + 13

The solutions to the quadratic equation are:

x = 3 - 13, x = 3 + 13

- 0.08 x^{2} + 2.784 x + 1.7 = 0

(x - 1)^{2} - 49 = 1

\frac{x}{2} + 10 = - x^{2} + 15

w^{2} + 11 w = - 28

2 z \cdot 2 z - 2 z = 12

What are the solutions to the equation 4+6x-x^2=0 ?
The solutions to the equation 4+6x-x^2=0 are x=3-sqrt(13),x=3+sqrt(13)
Find the zeros of 4+6x-x^2=0
The zeros of 4+6x-x^2=0 are x=3-sqrt(13),x=3+sqrt(13)