What are the solutions to the equation (-3x+3)^2=36 ?

The solutions to the equation (-3x+3)^2=36 are x=-1,x=3

Find the zeros of (-3x+3)^2=36

The zeros of (-3x+3)^2=36 are x=-1,x=3

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(- 3 x + 3)^{2} = 36

x = - 1, x = 3

Solution steps

(- 3 x + 3)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

- 3 x + 3 = 36 : x = - 1

Solve

- 3 x + 3 = - 36 : x = 3

The solutions to the quadratic equation are:

x = - 1, x = 3

4 p^{2} = 2 - 5 p

x, 2 x^{2} + 2 y^{2} + 2 z^{2} = 8 x - 24 z + 1

2 x^{1} - x^{2} = 0

0.1 x^{2} + 0.2 x - 44 = 0

10 (x^{2} + 1) = 1

What are the solutions to the equation (-3x+3)^2=36 ?
The solutions to the equation (-3x+3)^2=36 are x=-1,x=3
Find the zeros of (-3x+3)^2=36
The zeros of (-3x+3)^2=36 are x=-1,x=3