What are the solutions to the equation m^2+8m-9=0 ?

The solutions to the equation m^2+8m-9=0 are m=1,m=-9

Find the zeros of m^2+8m-9=0

The zeros of m^2+8m-9=0 are m=1,m=-9

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m^{2} + 8 m - 9 = 0

m = 1, m = - 9

Solution steps

m^{2} + 8 m - 9 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 9) = 10

m_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 8 + 10}{2 \cdot 1}, m_{2} = \frac{- 8 - 10}{2 \cdot 1}

m = \frac{- 8 + 10}{2 \cdot 1} : 1

m = \frac{- 8 - 10}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

m = 1, m = - 9

151 t - 16 t^{2} = 88

\frac{2 - 3 x}{7} = x (1 - x)

x^{2} - 9 - 36 = 0

(5 x + 2) (x - 1) = 0

49 x^{2} - 225 = 0

What are the solutions to the equation m^2+8m-9=0 ?
The solutions to the equation m^2+8m-9=0 are m=1,m=-9
Find the zeros of m^2+8m-9=0
The zeros of m^2+8m-9=0 are m=1,m=-9