What are the solutions to the equation (p+5)^2=4 ?

The solutions to the equation (p+5)^2=4 are p=-3,p=-7

Find the zeros of (p+5)^2=4

The zeros of (p+5)^2=4 are p=-3,p=-7

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(p + 5)^{2} = 4

p = - 3, p = - 7

Solution steps

(p + 5)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

p + 5 = 4 : p = - 3

Solve

p + 5 = - 4 : p = - 7

The solutions to the quadratic equation are:

p = - 3, p = - 7

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x, 24 x y - 3 y^{2} + 4 x^{2} - 156 = 0

x^{2} + 32 x - 64 = 0

x^{2} - 2 (m - 1) x - 2 m - 1 = 0

What are the solutions to the equation (p+5)^2=4 ?
The solutions to the equation (p+5)^2=4 are p=-3,p=-7
Find the zeros of (p+5)^2=4
The zeros of (p+5)^2=4 are p=-3,p=-7